- Great circle
- 6,866 km
- 4,267 mi
- Estimated in the air
- 9h 02m
- block time
- Furthest from equator
- 50.2°N
- at 48% along
- One lap of Earth
- 17.1%
- of 40,075 km
Of the 292 routes catalogued here, this is the 96th longest.
What the aircraft actually flies over
From Rome the path crosses France, then 3,777 km of open water, then Canada, then 429 km of open water, then the United States.
The furthest the great circle gets from the equator is 50.2°N, 48% of the way along.
Flying the line that looks straight on a Mercator map — one constant compass bearing — would cover 7,196 km. That is 330 km further, about 5% more, and roughly 25m of extra flying.
Leaving Rome the aircraft points north-west (301°); it arrives into New York heading south-west (238°). That is 63° of drift without a single turn — the compass moves because the path is a curve on a sphere, not because the aircraft does.
FCO
Rome–Fiumicino Leonardo da Vinci
Rome, Italy · Europe
41.8°N, 12.3°E
JFK
John F. Kennedy
New York, United States · North America
40.6°N, 73.8°W
Rome to New York, asked and answered
- How far is Rome to New York?
- Rome to New York (FCO to JFK) is 6,866 km, or 4,267 mi, measured as great circle distance between the two airports.
- How long is the flight from Rome to New York?
- About 9h 02m in the air. That is an estimate from the distance at a typical airliner block speed, plus half an hour for taxi, climb and descent; published schedules vary with winds and routing.
- What route does a Rome to New York flight take?
- The great circle passes over France, then 3,777 km of open water, then Canada, then 429 km of open water, then the United States. It reaches 50.2°N at its furthest from the equator.
Where these numbers come from
Distances are computed from the two airports’ own coordinates, not looked up from published routes. Times are estimates, not schedules.
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